Question 146: Electrostats & Capacitance

Question

A galvanometer $(G)$ of $2 \Omega$ resistance is connected in the given circuit. The ratio of charge stored in $C_1$ and $C_2$ is :

Accepted Answer

In steady state
$$
\begin{aligned}
& { R_{eq} }=12 \Omega \\
& I=\frac{6}{12}=0.5 \mathrm{~A}
\end{aligned}
$$
P.D across $C_1=3 \mathrm{~V}$
P.D acoross $\mathrm{C}_2=4 \mathrm{~V}$
$$
\begin{aligned}
& \mathrm{q}_1=\mathrm{C}_1 \mathrm{~V}_1=12 \mu \mathrm{C} \\
& \mathrm{q}_2=\mathrm{C}_2 \mathrm{~V}_2=24 \mu \mathrm{C}
\end{aligned}
$$
$$
\frac{\mathrm{q}_1}{\mathrm{q}_2}=\frac{1}{2}
$$

Answer

1

Answer

$\frac{2}{3}$

Answer

$\frac{3}{2}$

Answer

$\frac{1}{2}$

Electrostats & Capacitance

A galvanometer (G) of 2 \Omega resistance is connected in the given circuit. The ratio of charge stored in C_1 and C_2 is :

Choose the correct answer: