Question 834: Electrostats & Capacitance

Question

90 J of work is done to move an electric charge of magnitude 3 C from a place A , where potential is -10 V to another place B , where potential is ' $\mathrm{V}_1$ ' volt. The value of $\mathrm{V}_1$ is

Accepted Answer

The work done to move a charge in an electric field is related to the change in electric potential by the equation:
$$ W = q \Delta V $$
where:
$ W = 90 \, 	ext{J} $ (work done),
$ q = 3 \, 	ext{C} $ (charge),
$ \Delta V = V_1 - (-10 \, 	ext{V}) = V_1 + 10 \, 	ext{V} $ (change in electric potential).
We can solve for $ V_1 $ using the formula:
$$ 90 = 3(V_1 + 10) $$
Divide both sides by 3:
$$ 30 = V_1 + 10 $$
Subtract 10 from both sides:
$$ V_1 = 20 \, 	ext{V} $$
Thus, the value of $ V_1 $ is 20 V, corresponding to Option B.

Answer

10 V

Answer

20 V

Answer

30 V

Answer

$-$40 V

Electrostats & Capacitance

90 J of work is done to move an electric charge of magnitude 3 C from a place A , where potential is -10 V to another place B , where potential is ' \mathrm{V}_1 ' volt. The value of \mathrm{V}_1 is

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