Question 549: Electrostats & Capacitance

Question

An electric dipole of moment
$$\overrightarrow p  = \left( { - \widehat i - 3\widehat j + 2\widehat k} ight) 	imes {10^{ - 29}} $$ C.m is at the origin
(0, 0, 0). The electric field due to this dipole at
$$\overrightarrow r  =  + \widehat i + 3\widehat j + 5\widehat k$$ (note that $$\overrightarrow r .\overrightarrow p  = 0$$ ) is parallel to :

Accepted Answer

Since $$\overrightarrow r $$
and $$\overrightarrow p $$
are perpendicular to each other
therefore point lies on the equitorial plane.
Therefore electric field at the point will be
antiparallel to the dipole moment.
$$ 	herefore $$ $$\overrightarrow E || - \overrightarrow p $$
$$ \Rightarrow $$ $$\overrightarrow E ||\left( {\widehat i + 3\widehat j - 2\widehat k} ight)$$

Answer

$$\left( { + \widehat i + 3\widehat j - 2\widehat k} \right)$$

Answer

$$\left( { + \widehat i - 3\widehat j - 2\widehat k} \right)$$

Answer

$$\left( { - \widehat i + 3\widehat j - 2\widehat k} \right)$$

Answer

$$\left( { - \widehat i - 3\widehat j + 2\widehat k} \right)$$

Electrostats & Capacitance

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