Question 280: Electrostats & Capacitance

Question

In the figure shown below, the charge on the left plate of the 10$$\mu $$F capacitor is –30$$\mu $$C. The charge on the right plate of the 6 $$\mu $$F capacitor is :

Accepted Answer

6$$\mu $$F & 4$$\mu $$F are in parallel & total charge on this combination is 30 $$\mu $$C
$$ 	herefore $$  Charge on 6$$\mu $$F capacitor = $${6 \over {6 + 4}} 	imes 30$$
= 18 $$\mu $$C
Since charge is asked on right plate therefore is +18$$\mu $$C

Answer

+ 12 $$\mu $$C

Answer

+ 18 $$\mu $$C

Answer

$$-$$ 18 $$\mu $$C

Answer

$$-$$ 12 $$\mu $$C

Electrostats & Capacitance

In the figure shown below, the charge on the left plate of the 10$\mu F capacitor is –30\mu C. The charge on the right plate of the 6 \mu $F capacitor is :

Choose the correct answer: