Question 575: Electrostats & Capacitance

Question

The electric field in a region is given by
$$\mathop E\limits^ 	o   = \left( {Ax + B} ight)\mathop i\limits^ \wedge  $$
, where E is in NC–1 and x is in
metres. The values of constants are
A = 20 SI unit and B = 10 SI unit. If the potential
at x = 1 is V1 and that at x = –5 is V2, then
V1 – V2 is :-

Accepted Answer

$$\overrightarrow E  = (20x + 10)\widehat i$$
$${V_1} - {V_2} =  - \int\limits_{ - 5}^1 {\left( {20x + 10} \right)dx} $$
$${V_1} - {V_2} =  - \left( {10{x^2} + 10x} \right)_{ - 5}^1$$
$${V_1} - {V_2} = 10\left( {25 - 5 - 1 - 1} \right)$$
$${V_1} - {V_2} = 180\,V$$

Answer

–520 V

Answer

180 V

Answer

–48 V

Answer

320 V

Electrostats & Capacitance

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