Question 794: Electrostats & Capacitance

Question

A hollow cylinder has charge ' $q$ ' $C$ within it. If ' $\phi$ ' is the electric flux associated with the curved

Accepted Answer

As per Gauss' law the net flux through closed surface is,
$$\phi_A+\phi_B+\phi_C=\frac{q}{\varepsilon_0}$$
Due to symmetry, the same flux passes through plane surfaces A and C , i.e., $\phi_{\mathrm{A}}=\phi_{\mathrm{C}}$
$$\begin{aligned}
	herefore \quad & 2 \phi_A+\phi=\frac{q}{\varepsilon_0} \quad \ldots\left(	ext { Given: } \phi_{\mathrm{B}}=\phiight)
\
& \phi_A=\frac{1}{2}\left(\frac{q}{\varepsilon_0}-\phiight) 
\end{aligned}$$

Answer

$\frac{1}{2}\left(\frac{\mathrm{q}}{\varepsilon_0}-\phi\right)$

Answer

$\frac{q}{2 \varepsilon_0}$

Answer

$\frac{\phi}{3}$

Answer

$\frac{q}{\varepsilon_0}-\phi$

Electrostats & Capacitance

A hollow cylinder has charge ' q ' C within it. If ' \phi ' is the electric flux associated with the curved

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