Question 618: Electrostats & Capacitance

Question

Five capacitors each of capacity $$C$$ are connected as shown in figure. If their resultant capacity is $$2 \mu \mathrm{F}$$, then the capacity of each condenser is

Accepted Answer

Given that the resultant capacitance $ C_{	ext{eq}} = 2 \, \mu 	ext{F} $:
The capacitors are connected in series. Therefore, the formula for the equivalent capacitance of capacitors in series is:
$ \frac{1}{C_{	ext{eq}}} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} + \frac{1}{C} + \frac{1}{C} $
This simplifies to:
$ \frac{1}{C_{	ext{eq}}} = \frac{5}{C} $
Substitute the given equivalent capacitance:
$ \frac{1}{2 \, \mu 	ext{F}} = \frac{5}{C} $
Solving for $ C $:
$ C = 10 \, \mu 	ext{F} $
Therefore, each capacitor has a capacitance of $ 10 \, \mu 	ext{F} $.

Answer

5 $$\mu$$F

Answer

2 $$\mu$$F

Answer

2.5 $$\mu$$F

Answer

10 $$\mu$$F

Electrostats & Capacitance

Five capacitors each of capacity $C are connected as shown in figure. If their resultant capacity is 2 \mu \mathrm{F}$, then the capacity of each condenser is

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