Question 886: Electrostats & Capacitance

Question

A uniformly charged half ring of a radius ' $R$ ' has linear charge density '$$\sigma$$'. The electric potential at the centre of the half ring is ( $$\epsilon_0=$$ permittivity of free space)

Accepted Answer

If $$\mathrm{q}$$ is the charge on the ring, then the potential at the centre is given by
$$\mathrm{V}=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{\mathrm{q}}{\mathrm{R}}$$
$$\begin{aligned}
& 	ext { But } q=\sigma 	imes \pi R \
& 	herefore V=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{ho \pi R}{R}=\frac{\sigma}{4 \varepsilon_0}
\end{aligned}$$

Answer

$$\frac{\sigma}{6 \epsilon_0}$$

Answer

$$\frac{\sigma}{2 \epsilon_0}$$

Answer

$$\frac{\sigma}{\epsilon_0}$$

Answer

$$\frac{\sigma}{4 \epsilon_0}$$

Electrostats & Capacitance

A uniformly charged half ring of a radius ' R ' has linear charge density '$\sigma'. The electric potential at the centre of the half ring is ( \epsilon_0=$ permittivity of free space)

Choose the correct answer: