Question 819: Electrostats & Capacitance

Question

Two surfaces A and B are enclosing the charges as shown below. The total normal electric induction (T.N.E.I) through the surfaces A and B are respectively.

Accepted Answer

Total normal electric induction is given by,
T.N.E.I. $=\sum \mathrm{q}_{	ext {enclosed }}$
$	herefore \quad$ T.N.E.I. for $A=(+2 q-q)=+q$
T.N.E.I. for $B=(+3 q-q)=+2 q$

Answer

$+2 q$ and $+2 q$

Answer

$+q$ and $+3 q$

Answer

$+q$ and $+2 q$

Answer

$+2 q$ and $+3 q$

Electrostats & Capacitance

Two surfaces A and B are enclosing the charges as shown below. The total normal electric induction (T.N.E.I) through the surfaces A and B are respectively.

Choose the correct answer: