Question 447: Electrostats & Capacitance

Question

A charge of $$4 \,\mu \mathrm{C}$$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be :

Accepted Answer

so $$F = {{kq(4 - q) 	imes {{10}^{ - 12}}} \over {{r^2}}}$$
so F
max
will be at q = 2 $$\mu$$C

Answer

$$1 \,\mu \mathrm{C}$$ and $$3 \,\mu\mathrm{C}$$

Answer

$$2 \,\mu \mathrm{C}$$ and $$2\, \mu \mathrm{C}$$

Answer

0 and $$4\, \mu\, \mathrm{C}$$

Answer

$$1.5 \,\mu \mathrm{C}$$ and $$2.5\, \mu \mathrm{C}$$

Electrostats & Capacitance

A charge of $4 \,\mu \mathrm{C}$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be :

Choose the correct answer: