Question 186: Electrostats & Capacitance

Question

A force of 10 N acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be.

Accepted Answer

E between two plates is $${\sigma  \over {{\varepsilon _0}}}$$ and due to one plate is $${\sigma  \over {2{\varepsilon _0}}}$$ so the force will be halved
So new force F = 5 N

Answer

5 N

Answer

10 N

Answer

20 N

Answer

Zero

Electrostats & Capacitance

A force of 10 N acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be.

Choose the correct answer: