Question 817: Electrostats & Capacitance

Question

The electric flux over a sphere of radius ' $r$ ' is ' $\phi$ '. If the radius of the sphere is doubled without changing the charge, the flux will be

Accepted Answer

Using Gauss's Law, the electric flux through a closed surface is given by:
$ \phi = \frac{q}{\varepsilon_0} $
where $ q $ is the charge enclosed by the surface, and $\varepsilon_0$ is the permittivity of free space.
From this expression, we see that the electric flux $\phi$ is directly proportional to the charge $ q $, and is independent of the size or shape of the Gaussian surface itself.
Thus, if the radius of the sphere is doubled and the charge $ q $ remains the same, the electric flux will remain unchanged. Therefore, the new flux $\phi_2$ is equal to the original flux $\phi$:
$ \phi_2 = \phi $

Answer

$4 \phi$

Answer

$2 \phi$

Answer

$\phi$

Answer

$\frac{\phi}{2}$

Electrostats & Capacitance

The electric flux over a sphere of radius ' r ' is ' \phi '. If the radius of the sphere is doubled without changing the charge, the flux will be

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