Question 868: Electrostats & Capacitance

Question

The electric field intensity on the surface of a charged solid sphere of radius '$$r$$' and volume charge dentiy '$$\rho$$' is given by ($$\epsilon_0=$$ permittivity of free space)

Accepted Answer

The electric field intensity on the surface is given by
$$\begin{aligned}
& E=\frac{1}{4 \pi \varepsilon_0} \frac{q}{r^2} \quad 	ext{.... (1)}\
\end{aligned}$$
But $$\mathrm{q}=\frac{4}{3} \pi \mathrm{r}^3 ho$$
Putting this value of $$\mathrm{q}$$ in Eq.(1) and simplifying we get
$$\mathrm{E}=\frac{\mathrm{ho r}}{3 \varepsilon_0}$$

Answer

zero

Answer

$$\frac{\sigma \pi}{3 \epsilon_0}$$

Answer

$$\frac{1}{4 \pi \epsilon_0} \frac{\sigma}{r}$$

Answer

$$\frac{5 \pi}{6 \epsilon_0}$$

Electrostats & Capacitance

The electric field intensity on the surface of a charged solid sphere of radius '$r' and volume charge dentiy '\rho' is given by (\epsilon_0=$ permittivity of free space)

Choose the correct answer: