Question 884: Electrostats & Capacitance

Question

A hollow charged metal sphere has radius 'R'. If the potential difference between its surface and a point at a distance '5 R' from the centre is $$\mathrm{V}$$, then magnitude of electric field Intensity at a distance '5R' from the centre of sphere is

Accepted Answer

$$\begin{aligned} V & =\frac{1}{4 \pi \epsilon_0} \frac{q}{R}-\frac{1}{4 \pi \epsilon_0} \frac{q}{5 R} \ & =\frac{1}{4 \pi \epsilon_0} \frac{q}{R}\left(1-\frac{1}{5}ight) \ & =\frac{1}{4 \pi \epsilon_0} \frac{q}{R} \frac{4}{5} \ E & =\frac{1}{4 \pi \varepsilon_0} \cdot \frac{q}{25 R^2} \ 	herefore \frac{E}{V} & =\frac{1}{20 R} 	ext { or } E=\frac{V}{20 R}\end{aligned}$$

Answer

$$\frac{V}{2 R}$$

Answer

$$\frac{\mathrm{V}}{20 \mathrm{R}}$$

Answer

$$10 \mathrm{VR}$$

Answer

$$20 \mathrm{VR}$$

Electrostats & Capacitance

A hollow charged metal sphere has radius 'R'. If the potential difference between its surface and a point at a distance '5 R' from the centre is $\mathrm{V}$, then magnitude of electric field Intensity at a distance '5R' from the centre of sphere is

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