Question 844: Electrostats & Capacitance

Question

In the electric field due to a charge $$Q$$, a charge $$q$$ moves from point $$A$$ to $$B$$. The work done is ( $$\varepsilon_0=$$ permittivity of vacuum)

Accepted Answer

The electric field due to a single charge has point symmetry, or single charged forms spherical equipotential surface.
The work done in moving a charge on this spherical surface is always zero.

Answer

$$\frac{1}{4 \pi \varepsilon_0} \frac{Q q}{r^2}$$

Answer

$$\frac{1}{4 \pi \varepsilon_0} \frac{Q q}{r} 	imes \frac{\pi}{6}$$

Answer

$$\frac{1}{4 \pi \varepsilon_0} \frac{Q q}{r}$$

Answer

Zero

Electrostats & Capacitance

In the electric field due to a charge $Q, a charge q moves from point A to B. The work done is ( \varepsilon_0=$ permittivity of vacuum)

Choose the correct answer: