Question 584: Electrostats & Capacitance

Question

The plates of a parallel plate capacitor of capacity '$$\mathrm{C}_1$$' are moved closer together until they ant half their original separation. The new capacitance '$$\mathrm{C}_2$$' is

Accepted Answer

The capacitance of a parallel plate capacitor is given by
$$\mathrm{C=\frac{k A_0}{d}}$$
If the distance between the plates $$\mathrm{d}$$ is decreased to half, the capacitance will become double.

Answer

$$\mathrm{C}_2=\frac{C_1}{2}$$

Answer

$$\mathrm{C}_2=\mathrm{C}_1$$

Answer

$$\mathrm{C}_2=2 \mathrm{C}_1$$

Answer

$$\mathrm{C}_2=3 \mathrm{C}_1$$

Electrostats & Capacitance

The plates of a parallel plate capacitor of capacity '$\mathrm{C}_1' are moved closer together until they ant half their original separation. The new capacitance '\mathrm{C}_2$' is

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