Question 221: Units , Dimensions and Error Analysis

Question

Dimensions of $${1 \over {{\mu _0}{\varepsilon _0}}}$$, where symbols have their usual meaning, are

Accepted Answer

The velocity of light in vacuum is
c = $${1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$;
$$	herefore[{1 \over {{\mu _0}{\varepsilon _0}}}]$$ = [c
2
] = [L
2
T
-2
]
$$	herefore$$ Dimension of $${1 \over {{\mu _0}{\varepsilon _0}}}$$ = [L
2
T
-2
]

Answer

[ L-1T ]

Answer

[ L-2T2 ]

Answer

[ L2T-2 ]

Answer

[ LT-1 ]

Units , Dimensions and Error Analysis

Dimensions of ${1 \over {{\mu _0}{\varepsilon _0}}}$, where symbols have their usual meaning, are

Choose the correct answer: