Question 16: Units , Dimensions and Error Analysis

Question

If the binding energy per nucleon in $3 \mathrm{Li}^7$ and ${ }_2 \mathrm{He}^4$ nuclei are respectively 5.60 MeV and 7.06 MeV , then energy of $p$ in the reaction $p+{ }_3 \mathrm{Li}^7 \rightarrow 2{ }_2 \mathrm{He}^4$ is

Accepted Answer

LetÃ¢ÂÂs compute the QÃ¢ÂÂvalue step by step:
Binding energy of
Li-7 = 7Ã¢ÂÂÃÂÃ¢ÂÂ5.60 MeV = 39.20 MeV
Binding energy of one He-4 = 4Ã¢ÂÂÃÂÃ¢ÂÂ7.06 MeV = 28.24 MeV
Ã¢ÂÂ two He-4Ã¢ÂÂs = 2Ã¢ÂÂÃÂÃ¢ÂÂ28.24 MeV = 56.48 MeV
Q-value = BE(products) Ã¢ÂÂ BE(reactants)
= 56.48 MeV Ã¢ÂÂ (39.20 MeV + 0)
= 17.28 MeV
So the reaction releases 17.28 MeV.
Answer: Option D (17.28 MeV).

Answer

12.28 MeV

Answer

13.28 MeV

Answer

28.28 MeV

Answer

17.28 MeV

Units , Dimensions and Error Analysis

If the binding energy per nucleon in 3 \mathrm{Li}^7 and { }_2 \mathrm{He}^4 nuclei are respectively 5.60 MeV and 7.06 MeV , then energy of p in the reaction p+{ }_3 \mathrm{Li}^7 \rightarrow 2{ }_2 \mathrm{He}^4 is

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