Question 31: Motion in 1D

Question

A particle starts with an initial velocity of $$10.0 \mathrm{~ms}^{-1}$$ along $$x$$-direction and accelerates uniformly at the rate of $$2.0 \mathrm{~ms}^{-2}$$. The time taken by the particle to reach the velocity of $$60.0 \mathrm{~ms}^{-1}$$ is __________.

Accepted Answer

To find the time taken by the particle to reach the velocity of $$60.0 \mathrm{~ms}^{-1}$$, we can use the formula:
$$
v = u + at
$$
Where:
$$v$$ is the final velocity,
$$u$$ is the initial velocity,
$$a$$ is the acceleration, and
$$t$$ is the time taken.
Plugging in the given values:
$$
60.0 \mathrm{~ms}^{-1} = 10.0 \mathrm{~ms}^{-1} + 2.0 \mathrm{~ms}^{-2} \cdot t
$$
Solve for $$t$$:
$$
50.0 \mathrm{~ms}^{-1} = 2.0 \mathrm{~ms}^{-2} \cdot t
$$
$$
t = \frac{50.0 \mathrm{~ms}^{-1}}{2.0 \mathrm{~ms}^{-2}} = 25 \mathrm{s}
$$
So, the time taken by the particle to reach the velocity of $$60.0 \mathrm{~ms}^{-1}$$ is 25 seconds.

Answer

30s

Answer

6s

Answer

3s

Answer

25s

Motion in 1D

A particle starts with an initial velocity of $10.0 \mathrm{~ms}^{-1} along x-direction and accelerates uniformly at the rate of 2.0 \mathrm{~ms}^{-2}. The time taken by the particle to reach the velocity of 60.0 \mathrm{~ms}^{-1}$ is __________.

Choose the correct answer: