Question 36: Motion in 1D

Question

A car travels a distance of '$$x$$' with speed $$v_1$$ and then same distance '$$x$$' with speed $$v_2$$ in the same direction. The average speed of the car is :

Accepted Answer

$$
\begin{aligned}
& 	ext { Average velocity }=\frac{	ext { Total displacement }}{	ext { Total time }} \\
& =\frac{\mathrm{x}+\mathrm{x}}{\frac{\mathrm{x}}{\mathrm{v}_1}+\frac{\mathrm{x}}{\mathrm{v}_2}}=\frac{2 \mathrm{v}_1 \mathrm{v}_2}{\mathrm{v}_1+\mathrm{v}_2}
\end{aligned}
$$

Answer

$${{{v_1}{v_2}} \over {2({v_1} + {v_2})}}$$

Answer

$${{2{v_1}{v_2}} \over {{v_1} + {v_2}}}$$

Answer

$${{2x} \over {{v_1} + {v_2}}}$$

Answer

$${{{v_1} + {v_2}} \over 2}$$

Motion in 1D

A car travels a distance of '$x' with speed v_1 and then same distance 'x' with speed v_2$ in the same direction. The average speed of the car is :

Choose the correct answer: