Question 1: Motion in 2D & Vectors

Question

Assertion The maximum height of projectile
is always 25% of the maximum range.
Reason For maximum range, projectile
should be projected at 90°.

Accepted Answer

To obtain maximum range, angle of projection must be $$45^{\circ}$$, i.e. $$	heta=45^{\circ}$$.
$$	herefore H_{\max }=\frac{u^2 \sin ^2 45^{\circ}}{2 g}=\frac{u^2}{2 g}\left(\frac{1}{\sqrt{2}}ight)^2=\frac{u^2}{4 g}=\frac{R_{\max }}{4}$$
So, $$H_{\max }$$ is $$25 \%$$ of $$R_{\max }$$.

Answer

Both Assertion and Reason are correct, Reason is the correct explanation of Assertion

Answer

Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

Answer

Assertion is correct and Reason is incorrect

Answer

Assertion is incorrect and Reason is correct

Motion in 2D & Vectors

Assertion The maximum height of projectile is always 25% of the maximum range. Reason For maximum range, projectile should be projected at 90°.

Choose the correct answer: