Question 124: Motion in 2D & Vectors

Question

A vector $P$ has $X$ and $Y$ components of magnitude 2 units and 4 units respectively. A vector $Q$ along negative $X$-axis has magnitude 6 units. The vector $(\mathbf{Q}-\mathbf{P})$ will be

Accepted Answer

According to question, vectors $\mathbf{P}$ and $\mathbf{Q}$ can be written as
$$\begin{array}{rlrl} 
& \mathbf{P} =2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}} \
	ext { and } & \quad \mathbf{Q} =-6 \hat{\mathbf{i}} \
	herefore & \mathbf{Q}-\mathbf{P} =-6 \hat{\mathbf{i}}-(2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \
& =-8 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}=-4(2 \hat{\mathbf{i}}+\hat{\mathbf{j}})
\end{array}$$

Answer

$4(2 \hat{i}-\hat{j})$

Answer

$-4(2 \hat{\mathbf{i}}-\hat{\mathrm{j}})$

Answer

$4(2 \hat{i}+\hat{j})$

Answer

$-4(2 \hat{i}+\hat{j})$

Motion in 2D & Vectors

A vector P has X and Y components of magnitude 2 units and 4 units respectively. A vector Q along negative X-axis has magnitude 6 units. The vector (\mathbf{Q}-\mathbf{P}) will be

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