Question 122: Motion in 2D & Vectors

Question

The vectors $(\mathbf{A}+\mathbf{B})$ and $(\mathbf{A}-\mathbf{B})$ are at right. angles to each other. This is possible under the condition

Accepted Answer

Vectors $(\mathbf{A}+\mathbf{B})$ and $(\mathbf{A}-\mathbf{B})$ are at right angle to each other, therefore
$$\begin{aligned}
& (A+B) \cdot(A-B)=0 \
& A \cdot A+B \cdot A-A \cdot B-B \cdot B=0 \
& |A|+B A \cos 	heta-A B \cos 	heta-|B|^2=0 \
& |A|^2=|B|^2 \
	ext{Hence,}\quad& |A|=|B|
\end{aligned}$$

Answer

$|A|=|B|$

Answer

$A \cdot B=0$

Answer

$A \cdot B=1$

Answer

$A 	imes B=0$

Motion in 2D & Vectors

The vectors (\mathbf{A}+\mathbf{B}) and (\mathbf{A}-\mathbf{B}) are at right. angles to each other. This is possible under the condition

Choose the correct answer: