Question 186: Motion in 2D & Vectors

Question

The speed of a projectile at its maximum height is half of its initial  speed. The angle of projection is

Accepted Answer

Let v be velocity of a projectile at maximum
height H.
v = ucos$$	heta $$
According to given problem, $$v = {u \over 2}$$
$$ 	herefore $$ $${u \over 2} = u\cos 	heta  \Rightarrow \cos 	heta  = {1 \over 2} \Rightarrow 	heta  = 60^\circ $$

Answer

60o

Answer

15o

Answer

30o

Answer

45o

Motion in 2D & Vectors

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is

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