Question 136: Motion in 2D & Vectors

Question

A projectile can have the same range 'R' for two angles of projection. If T1 and T2 be the time
of flights in the two cases, then the product of the two time of flights is directly proportional to

Accepted Answer

Range is same for angle of projection $$	heta ,$$ and $${90^ \circ } - 	heta $$
$${T_1} = {{2u\sin 	heta } \over g},\,\,{T_2} = {{2u\cos 	heta } \over g}$$
$${T_1}{T_2} =$$ $${{4{u^2}\sin 	heta \cos 	heta } \over {{g^2}}}$$
= $${2 \over g} 	imes \left( {{{{u^2}\sin 2	heta } \over g}} ight)$$
= $${{2R} \over g}$$
(as $$R = $$$${{{{u^2}\sin 2	heta } \over g}}$$ )
Hence, $${T_1}{T_2}$$ is proportional to $$R.$$

Answer

R

Answer

$${1 \over R}$$

Answer

$${1 \over {{R^2}}}$$

Answer

$${R^2}$$

Motion in 2D & Vectors

A projectile can have the same range 'R' for two angles of projection. If T1 and T2 be the time of flights in the two cases, then the product of the two time of flights is directly proportional to

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