Question 192: Motion in 2D & Vectors

Question

$$\overrightarrow A $$ and $$\overrightarrow B $$ are two vectors and $$	heta $$ is the angle between them,  if $$\left| {\overrightarrow A  	imes \overrightarrow B } ight| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } ight),$$ the value of $$	heta $$ is

Accepted Answer

$$\left| {\overrightarrow A  	imes \overrightarrow B } ight| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } ight)$$
$$ 	herefore $$ $$AB\sin 	heta  = \sqrt 3 AB\cos 	heta $$
or $$	an 	heta  = \sqrt 3 $$ or $$	heta  = {	an ^{ - 1}}\sqrt 3  = 60^\circ $$;

Answer

45o

Answer

30o

Answer

90o

Answer

60o

Motion in 2D & Vectors

\overrightarrow A and \overrightarrow B are two vectors and \theta is the angle between them, if \left| {\overrightarrow A \times \overrightarrow B } \right| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } \right), the value of \theta $ is

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