Question 223: Work, Energy and Power & Circular Motion

Question

A particle rotates in a horizontal circle of radius 'R' in a conical funnel with constant speed 'V'. The inner surface of the funnel is smooth. The height of the plane of the circle from the vertex of the funnel is (g-acceleration due to gravity)

Accepted Answer

$$\begin{array}{ll} 
& 	ext { From figure, } \
& N \sin 	heta=m g \
& N \cos 	heta=\frac{m V^2}{R} \
	herefore \quad & 	an 	heta=\frac{\mathrm{Rg}}{\mathrm{~V}^2} \
	herefore \quad & \frac{\mathrm{R}}{\mathrm{~h}}=\frac{\mathrm{Rg}}{\mathrm{~V}^2} \
	herefore \quad & \mathrm{~h}=\frac{\mathrm{V}^2}{\mathrm{~g}}
\end{array}$$

Answer

$\frac{V}{g}$

Answer

$\frac{\mathrm{V}}{2 \mathrm{~g}}$

Answer

$\frac{\mathrm{V}^2}{2 \mathrm{~g}}$

Answer

$\frac{\mathrm{V}^2}{\mathrm{~g}}$

Work, Energy and Power & Circular Motion

A particle rotates in a horizontal circle of radius 'R' in a conical funnel with constant speed 'V'. The inner surface of the funnel is smooth. The height of the plane of the circle from the vertex of the funnel is (g-acceleration due to gravity)

Choose the correct answer: