Question 247: Work, Energy and Power & Circular Motion

Question

A particle is moving in a circle with uniform speed '$$v$$'. In moving from a point to another diametrically opposite point

Accepted Answer

At both points, the momentum will be $$\mathrm{mv}$$, but will be in opposite directions.
$$\begin{array}{rlrl}
	herefore & \Delta \mathrm{P}  =\mathrm{mv}-(-\mathrm{mv}) \
	herefore & \Delta \mathrm{P}=2 \mathrm{~mv}
\end{array}$$
The momentum changes by $$2 \mathrm{~mv}$$.

Answer

the momentum changes by $$\mathrm{mv}$$

Answer

the momentum changes by $$2 \mathrm{~mv}$$

Answer

the kinetic energy changes by $$\frac{1}{2} \mathrm{mv}^2$$

Answer

the kinetic energy changes by $$\mathrm{m v^2}$$

Work, Energy and Power & Circular Motion

A particle is moving in a circle with uniform speed '$v$'. In moving from a point to another diametrically opposite point

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