Question 90: Work, Energy and Power & Circular Motion

Question

As per the given figure, two blocks each of mass $$250 \mathrm{~g}$$ are connected to a spring of spring constant $$2 \,\mathrm{Nm}^{-1}$$. If both are given velocity $$v$$ in opposite directions, then maximum elongation of the spring is :

Accepted Answer

$$\because$$ Loss in KE = Gain in spring energy
$$ \Rightarrow {1 \over 2}m{v^2} 	imes 2 = {1 \over 2}kx_m^2$$
$$ \Rightarrow 2 	imes {1 \over 4} 	imes {v^2} = 2 	imes x_m^2$$
$$ \Rightarrow {x_m} = \sqrt {{{{v^2}} \over 4}}  = {v \over 2}$$

Answer

$$\frac{v}{2 \sqrt{2}}$$

Answer

$$\frac{v}{2}$$

Answer

$$\frac{v}{4}$$

Answer

$$
\frac{v}{\sqrt{2}}
$$

Work, Energy and Power & Circular Motion

As per the given figure, two blocks each of mass $250 \mathrm{~g} are connected to a spring of spring constant 2 \,\mathrm{Nm}^{-1}. If both are given velocity v$ in opposite directions, then maximum elongation of the spring is :

Choose the correct answer: