Question 200: Work, Energy and Power & Circular Motion

Question

A body of mass $$' m ',$$ acceleration uniformly from rest to $$'{v_1}'$$ in time $${T}$$. The instantaneous power delivered to the body as a function of time is given by

Accepted Answer

Assume acceleration of body be $$a$$
$$	herefore$$ $${v_1} = 0 + a{T} \Rightarrow a = {{{v_1}} \over {{T}}}$$
$$	herefore$$ $$v = at \Rightarrow v = {{{v_1}t} \over {{T}}}$$
$${P_{inst}} = \overrightarrow F .\overrightarrow v  = \left( {m\overrightarrow a } ight).\overrightarrow v $$
$$= \left( {{{m{v_1}} \over {{T}}}} ight)\left( {{{{v_1}t} \over {{T}}}} ight)$$
$$ = m{\left( {{{{v_1}} \over {{T}}}} ight)^2}t$$

Answer

$${{m{v_1}{t^2}} \over {{T}}}$$

Answer

$${{mv_1^2t} \over {T^2}}$$

Answer

$${{m{v_1}t} \over {{T}}}$$

Answer

$${{mv_1^2t} \over {{T}}}$$

Work, Energy and Power & Circular Motion

A body of mass $' m ', acceleration uniformly from rest to '{v_1}' in time {T}$. The instantaneous power delivered to the body as a function of time is given by

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