Question 206: Work, Energy and Power & Circular Motion

Question

A spring of spring constant $$5 	imes {10^3}\,N/m$$ is stretched initially by $$5$$ $$cm$$ from the unstretched position. Then the work required to stretch it further by another $$5$$ $$cm$$ is

Accepted Answer

Given $$k = 5 	imes {10^3}N/m$$
Work done when a spring stretched from x
1
cm to x
2
cm,
$$W = {1 \over 2}k\left( {x_2^2 - x_1^2} ight) $$
$$= {1 \over 2} 	imes 5 	imes {10^3}\left[ {{{\left( {0.1} ight)}^2} - {{\left( {0.05} ight)}^2}} ight]$$
$$ = {{5000} \over 2} 	imes 0.15 	imes 0.05 = 18.75\,\,Nm$$

Answer

$$12.50$$ $$N$$-$$m$$

Answer

$$18.75$$ $$N$$-$$m$$

Answer

$$25.00$$ $$N$$-$$m$$

Answer

$$625$$ $$N$$-$$m$$

Work, Energy and Power & Circular Motion

A spring of spring constant $5 \times {10^3}\,N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch it further by another 5 cm$ is

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