Question 109: Work, Energy and Power & Circular Motion

Question

A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r such that $$r = {L \over {\sqrt 2 }}$$. The speed of particle will be :

Accepted Answer

$$r = {l \over {\sqrt 2 }}$$
$$\sin 	heta  = {r \over l} = {l \over {\sqrt 2 }}$$
$$	heta$$ = 45$$^\circ$$
$$T\sin 	heta  = {{m{v^2}} \over r}$$
$$T\cos 	heta  = mg$$
$$	an 	heta  = {{{v^2}} \over {rg}} \Rightarrow v = \sqrt {rg} $$

Answer

$${\sqrt {rg} }$$

Answer

$${\sqrt {2rg} }$$

Answer

$${2\sqrt {rg} }$$

Answer

$${\sqrt {{{rg} \over 2}} }$$

Work, Energy and Power & Circular Motion

A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r such that $r = {L \over {\sqrt 2 }}$. The speed of particle will be :

Choose the correct answer: