Question 183: Work, Energy and Power & Circular Motion

Question

Radius of curved road is ' $R$ ', width of road is ' $b$ '. The outer edge of road is raised by ' $h$ ' with respect to inner edge so that a car with velocity ' $V$ ' can pass safe over it, then value of ' $h$ ' is ( $\mathrm{g}=$ acceleration due to gravity)

Accepted Answer

Banking of roads helps vehicles take turns safely by tilting the road surface. The required angle is given by $	an 	heta=\frac{\mathrm{v}^2}{\mathrm{Rg}}$
Where, ' $h$ ' is height of the outer edge from the inner edge and ' $b$ ' is the distance between the tracks or width of the road.
$$ 	an 	heta=\frac{h}{\left(b^2-h^2ight)^{1 / 2}} \approx \frac{h}{b} $$
$$ \begin{aligned} & \left(l^2 \gg \mathrm{~h}^2ight) \ 	herefore & \frac{\mathrm{h}}{\mathrm{~b}}=\frac{\mathrm{V}^2}{\mathrm{Rg}} \ 	herefore & \mathrm{~h}=\frac{\mathrm{V}^2 \mathrm{~b}}{\mathrm{Rg}} \end{aligned} $$

Answer

$\frac{\mathrm{V}^2 \mathrm{~b}}{\mathrm{Rg}}$

Answer

$\frac{\mathrm{V}}{\mathrm{Rgb}}$

Answer

$\frac{V^2 R}{g}$

Answer

$\frac{V^2 b}{g}$

Work, Energy and Power & Circular Motion

Radius of curved road is ' R ', width of road is ' b '. The outer edge of road is raised by ' h ' with respect to inner edge so that a car with velocity ' V ' can pass safe over it, then value of ' h ' is ( \mathrm{g}= acceleration due to gravity)

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