Question 665: Centre of Mass and Rotational Motion

Question

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is $$I$$0. Its moment of inertia about an axis passing  through one of its ends and perpendicular to its length is

Accepted Answer

By the theorem of parallel axes, the moment
of inertia of a body about any axis is equal to the
sum of the moment of inertia about a parallel axis
through the centre of mass and Ma
2
, where M is the mass of the body and a is the separation between
the two axes.
Therefore, the moment of inertia of the rod about
an axis passing through one of its ends and
perpendicular to its length is
I = I
0
+ M (L/2)
2
= I
0
+ ML
2
/4

Answer

$${I_0} + M{L^2}/2$$

Answer

$${I_0} + M{L^2}/4$$

Answer

$${I_0} + 2M{L^2}$$

Answer

$${I_0} + M{L^2}$$

Centre of Mass and Rotational Motion

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is $I$0. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

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