Question 164: Centre of Mass and Rotational Motion

Question

A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is

Accepted Answer

$$K{E_R} = {1 \over 2}l{w^2}$$
$$ = {1 \over 2} 	imes {2 \over 5} 	imes {\omega ^2} 	imes (m{R^2})$$
$$K{E_{total}} = {1 \over 2} 	imes {7 \over 5} 	imes m{R^2} 	imes {\omega ^2}$$
$$	herefore$$ $${{K{E_R}} \over {K{E_{total}}}} = {2 \over 7}$$

Answer

$${2 \over 5}$$

Answer

$${2 \over 7}$$

Answer

$${1 \over 5}$$

Answer

$${7 \over 10}$$

Centre of Mass and Rotational Motion

A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is

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