Question 351: Centre of Mass and Rotational Motion

Question

Two masses '$$m_{\mathrm{a}}$$' and '$$\mathrm{m}_{\mathrm{b}}$$' moving with velocities '$$v_{\mathrm{a}}$$' and '$$v_{\mathrm{b}}$$' opposite directions collide elastically. Alter the collision '$$m_a$$' and '$$m_b$$' move with velocities and '$$v_{\mathrm{b}}$$' and '$$v_a$$' respectively, then the ratio $$\mathrm{m_a:m_b}$$ is

Accepted Answer

When two bodies of equal masses collide elastically, they exchange their velocities. Since the two masses are exchanging their velocities, their masses must be equal.
Hence, $$\frac{\mathrm{m}_{\mathrm{a}}}{\mathrm{m}_{\mathrm{b}}}=1$$

Answer

$$\frac{v_a+v_b}{v_a-v_b}$$

Answer

$$\frac{1}{2}$$

Answer

1

Answer

$$\frac{v_a-v_b}{v_a+v_b}$$

Centre of Mass and Rotational Motion

Two masses '$m_{\mathrm{a}}' and '\mathrm{m}_{\mathrm{b}}' moving with velocities 'v_{\mathrm{a}}' and 'v_{\mathrm{b}}' opposite directions collide elastically. Alter the collision 'm_a' and 'm_b' move with velocities and 'v_{\mathrm{b}}' and 'v_a' respectively, then the ratio \mathrm{m_a:m_b}$ is

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