Question 568: Centre of Mass and Rotational Motion

Question

A particle of mass '$$\mathrm{m}$$' is rotating along a circular path of radius '$$r$$' having angular momentum '$$L$$'. The centripetal force acting on the particle is given by

Accepted Answer

$$\begin{aligned}
& 	ext { Centripetal force }=\mathrm{m}^2 \mathrm{r} \
& 	herefore \quad \omega=\frac{L}{I}=\frac{L}{\mathrm{mr}^2} \quad \ldots .(\because \mathrm{L}=\mathrm{I} \omega) \
& 	herefore \quad \mathrm{F}=\mathrm{m}\left(\frac{\mathrm{L}}{\mathrm{mr}^2}ight)^2 \mathrm{r}=\frac{\mathrm{mL}^2 \mathrm{r}}{\mathrm{m}^2 \mathrm{r}^4}=\frac{\mathrm{L}^2}{\mathrm{mr}^3}
\end{aligned}$$

Answer

$$\frac{\mathrm{L}^2}{\mathrm{mr}}$$

Answer

$$\frac{\mathrm{L}^2}{\mathrm{mr}^2}$$

Answer

$$\frac{\mathrm{mL}^2}{\mathrm{r}}$$

Answer

$$\frac{\mathrm{L}^2}{\mathrm{mr}^3}$$

Centre of Mass and Rotational Motion

A particle of mass '$\mathrm{m}' is rotating along a circular path of radius 'r' having angular momentum 'L$'. The centripetal force acting on the particle is given by

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