Question 544: Centre of Mass and Rotational Motion

Question

An annular ring has mass 10 kg and inner and outer radii are 10 m and 5 m respectively. Its moment of inertia about an axis passing through its centre and perpendicular to its plane is

Accepted Answer

$$\begin{aligned}
&	ext { The moment of inertia of the annular ring is }\
&\begin{aligned}
I & =\frac{1}{2} M\left(R_1^2+R_2^2ight) \
& =\frac{10(100+25)}{2}=625 \mathrm{~kgm}^2
\end{aligned}
\end{aligned}$$

Answer

$525 \mathrm{~kgm}^2$

Answer

$625 \mathrm{~kgm}^2$

Answer

$525 \mathrm{~gcm}^2$

Answer

$625 \mathrm{~gcm}^2$

Centre of Mass and Rotational Motion

An annular ring has mass 10 kg and inner and outer radii are 10 m and 5 m respectively. Its moment of inertia about an axis passing through its centre and perpendicular to its plane is

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