Question 487: Centre of Mass and Rotational Motion

Question

The moment of inertia of a solid sphere of mass ' $m$ ' and radius ' $R$ ' about its diametric axis is ' $I$ '. Its moment of inertia about a tangent in the plane is

Accepted Answer

M.I. of sphere about the diameter $=\frac{2}{5} \mathrm{MR}^2$
$\frac{2}{5} \mathrm{MR}^2=\mathrm{I}$ or $\mathrm{MR}^2=\frac{5}{2} \mathrm{I}$
According to theorem of parallel axes, M.I. about the tangent
$$ =I+\frac{5}{2} I=\frac{7}{2} I=3.5 I $$

Answer

2.5 I

Answer

3.0 I

Answer

3.5 I

Answer

4 I

Centre of Mass and Rotational Motion

The moment of inertia of a solid sphere of mass ' m ' and radius ' R ' about its diametric axis is ' I '. Its moment of inertia about a tangent in the plane is

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