Question 239: Centre of Mass and Rotational Motion

Question

A machine gun fires a bullet of mass $$40$$ $$g$$ with a velocity  $$1200m{s^{ - 1}}.$$ The man holding it can exert a maximum force of $$144$$ $$N$$ on the gun. How many bullets can he fire per second at the most?

Accepted Answer

Assume the man can fire $$n$$ bullets in one second.
$$	herefore$$ change in momentum per second $$ = n 	imes mv = F$$
[ $$m=$$ mass of bullet, $$v=$$ velocity, $$F$$ = force)  ]
$$	herefore$$ $$n = {F \over {mv}} = {{144 	imes 1000} \over {40 	imes 1200}} = 3$$

Answer

Two

Answer

Four

Answer

One

Answer

Three

Centre of Mass and Rotational Motion

A machine gun fires a bullet of mass $40 g with a velocity 1200m{s^{ - 1}}. The man holding it can exert a maximum force of 144 N$ on the gun. How many bullets can he fire per second at the most?

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