Question 389: Gravitation

Question

If $$\mathrm{R}$$ is the radius of the earth and $$\mathrm{g}$$ is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be :

Accepted Answer

$$
\begin{aligned}
& g=\frac{4}{3} \pi \mathrm{GR} ho \
& ho=\frac{3 g}{4 \pi \mathrm{GR}}
\end{aligned}
$$

Answer

$$\frac{\pi \mathrm{RG}}{12 \mathrm{~g}}$$

Answer

$$\frac{3 \pi R}{4 g G}$$

Answer

$$\frac{3 g}{4 \pi R G}$$

Answer

$$\frac{4 \pi \mathrm{G}}{3 g R}$$

Gravitation

If $\mathrm{R} is the radius of the earth and \mathrm{g}$ is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be :

Choose the correct answer: