Question 273: Gravitation

Question

The gravitational pull of the moon is $\left(\frac{1}{6}ight)^{th}$ of the earth and mass of moon is $\left(\frac{1}{8}ight)^{	ext {th }}$ of the earth. This implies that the

Accepted Answer

Gravitational pull depends upon the acceleration due to gravity on that planet.
$$ \begin{aligned} & & M_m & =\frac{1}{6} M_e, g_m=\frac{1}{8} g_e \ & 	herefore & \frac{R_e}{R_m} & =\left(\frac{M_e}{M_m} 	imes \frac{g_m}{g_e}ight)^{1 / 2}=\left(6 	imes \frac{1}{8}ight)^{1 / 2} \ & 	herefore & R_m & =\sqrt{\frac{4}{3}} R_e \end{aligned} $$

Answer

radius of moon is $(1 / 4)^{	ext {th }}$ of the earth's radius.

Answer

radius of the earth is $(\sqrt{4 / 3})^{	ext {th }}$ of the moon's radius.

Answer

moon's radius is half that of the earth.

Answer

radius of the earth is $(4 / 3)^{	ext {th }}$ of the moon's radius.

Gravitation

The gravitational pull of the moon is \left(\frac{1}{6}\right)^{th} of the earth and mass of moon is \left(\frac{1}{8}\right)^{\text {th }} of the earth. This implies that the

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