Question 339: Gravitation

Question

For a satellite orbiting around the earth in a circular orbit, the ratio of potential energy to kinetic energy at same height is

Accepted Answer

$$\begin{aligned}
& 	ext { K.E }=\frac{G M m}{2 r} \
& P . E=-\frac{G M m}{r} \
	herefore \quad & \frac{K . E}{|P . E|}=\frac{G M m}{2 r} 	imes \frac{r}{G M m} \
	herefore \quad \frac{P . E}{K . E} & =\frac{2}{1}=2
\end{aligned}$$

Answer

$$\frac{1}{\sqrt{2}}$$

Answer

$$\frac{1}{2}$$

Answer

$$\sqrt{2}$$

Answer

2

Gravitation

For a satellite orbiting around the earth in a circular orbit, the ratio of potential energy to kinetic energy at same height is

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