Question 129: Gravitation

Question

Two particles of equal mass '$$m$$' move in a circle of radius '$$r$$' under the action of their mutual gravitational attraction. The speed of each particle will be :

Accepted Answer

$\frac{\mathrm{Gm}^{2}}{4 \mathrm{r}^{2}}=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$
$$
v=\sqrt{\frac{G m}{4 r}}
$$

Answer

$$\sqrt{\frac{G m}{4 r}}$$

Answer

$$\sqrt{\frac{G m}{2 r}}$$

Answer

$$\sqrt{\frac{G m}{r}}$$

Answer

$$\sqrt{\frac{4 G m}{r}}$$

Gravitation

Two particles of equal mass '$m' move in a circle of radius 'r$' under the action of their mutual gravitational attraction. The speed of each particle will be :

Choose the correct answer: