Question 161: Properties of Matter

Question

If 'M' is the mass of water that rises in a capillary
tube of radius 'r', then mass of water which will
rise in a capillary tube of radius '2r' is :

Accepted Answer

Height of liquid rise in capillary tube $$h = {{2T\,\cos {	heta _c}} \over {ho rg}}$$
$$ \Rightarrow h \propto {1 \over r}$$
When radius becomes double height become half
$$ 	herefore $$ $${h^{'}} = {h \over 2}$$
Now, M = $$\pi $$r
2
h ÃÂ $$ho $$ and M
'
= $$\pi $$(2r)
2
(h/2) ÃÂ $$ho $$ = 2M

Answer

M

Answer

4M

Answer

M/2

Answer

2M

Properties of Matter

If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius '2r' is :

Choose the correct answer: