The surface tension of soap solution is $3.5 \times 10^{-2} \mathrm{~Nm}^{-1}. The amount of work done required to increase the radius of soap bubble from 10 \mathrm{~cm} to 20 \mathrm{~cm} is _________ \times ~10^{-4} \mathrm{~J}.
(\operatorname{take} \pi=22 / 7)
Choose the correct answer: