Question 185: Properties of Matter

Question

An open glass tube is immersed in mercury in such a way that a length of $$8$$ $$cm$$ extends above the mercury level. The open end of the tube is then closed and scaled and the tube is raised vertically up by additional $$46$$ $$cm$$. What will be length of the air column above mercury in the tube now? (Atmospheric pressure $$=76$$ $$cm$$ of $$Hg$$)

Accepted Answer

Length of the air column above mercury in the tube is,
$$P + x = {P_0}$$
$$ \Rightarrow P = \left( {76 - x} ight)$$
$$ \Rightarrow 8 	imes A 	imes 76 = \left( {76 - x} ight) 	imes A 	imes \left( {54 - x} ight)$$
$$	herefore$$ $$x=38$$
Thus, length of air column $$=54-38=16cm.$$

Answer

$$16$$ $$cm$$

Answer

$$22$$ $$cm$$

Answer

$$38$$ $$cm$$

Answer

$$6$$ $$cm$$

Properties of Matter

Choose the correct answer: