Question 904: Thermodynamics & KTG

Question

For an ideal gas, $$R=\frac{2}{3} C_v$$. This suggests that the gas consists of molecules, which are [$$\mathrm{R}=$$ universal gas constant]

Accepted Answer

For an ideal gas
$$\begin{aligned}
R & =C_p-C_v=\frac{2}{3} C_v \
	herefore C_p & =C_v+\frac{2}{3} C_v=\frac{5}{3} C_v \
	herefore \frac{C_p}{C_v} & =\frac{5}{3}
\end{aligned}$$
For a monoatomic gas $$\gamma=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=\frac{5}{3}$$

Answer

polyatomic

Answer

diatomic

Answer

monoatomic

Answer

a mixture of diatomic and polyatomic molecules

Thermodynamics & KTG

For an ideal gas, $R=\frac{2}{3} C_v. This suggests that the gas consists of molecules, which are [\mathrm{R}=$ universal gas constant]

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