Question 949: Thermodynamics & KTG

Question

Specific heats of an ideal gas at constant pressure and volume are denoted by $$\mathrm{C}_{\mathrm{p}}$$ and $$\mathrm{C}_{\mathrm{v}}$$ respectively. If $$\gamma=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}$$ and $$\mathrm{R}$$ it's the universal gas constant then $$\mathrm{C}_{\mathrm{v}}$$ is equal to

Accepted Answer

$$\begin{aligned} & \gamma=\frac{C_p}{C_v}, 	ext { Also } C_p-C_v=R \ & C_p=\gamma C_v \ 	herefore & \gamma C_v-C_v=R \quad 	herefore C_v(\gamma-1)=R \quad 	herefore C_v=\frac{R}{\gamma-1}\end{aligned}$$

Answer

$$\frac{(\gamma-1)}{(\gamma+1)}$$

Answer

$$\frac{(\gamma-1)}{\mathrm{R}}$$

Answer

$$\mathrm{R} \gamma$$

Answer

$$\frac{R}{(\gamma-1)}$$

Thermodynamics & KTG

Specific heats of an ideal gas at constant pressure and volume are denoted by $\mathrm{C}_{\mathrm{p}} and \mathrm{C}_{\mathrm{v}} respectively. If \gamma=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}} and \mathrm{R} it's the universal gas constant then \mathrm{C}_{\mathrm{v}}$ is equal to

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