Question 253: Thermodynamics & KTG

Question

$$N$$ moles of a polyatomic gas $$(f=6)$$ must be mixed with two moles of a monoatomic gas so that the mixture behaves as a diatomic gas. The value of $$N$$ is :

Accepted Answer

$$\mathrm{f}_{\mathrm{eq}}=\frac{\mathrm{n}_1 \mathrm{f}_1+\mathrm{n}_2 \mathrm{f}_2}{\mathrm{n}_1+\mathrm{n}_2}$$
For diatomic gas $$\mathrm{f}_{\mathrm{eq}}=5$$
$$\begin{aligned}
& 5=\frac{(\mathrm{N})(6)+(2)(3)}{\mathrm{N}+2} \
& 5 \mathrm{~N}+10=6 \mathrm{~N}+6 \
& \mathrm{~N}=4
\end{aligned}$$

Answer

6

Answer

2

Answer

4

Answer

3

Thermodynamics & KTG

N moles of a polyatomic gas (f=6) must be mixed with two moles of a monoatomic gas so that the mixture behaves as a diatomic gas. The value of N$ is :

Choose the correct answer: